Question 935579
Sheila needs 30 mL of a 19.2% acid solution for a chemistry experiment. She has a 12% acid solution and an 84% acid solution. How many milliliters of the 12% solution does she need to make the mixture?
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let x=amount of 12% solution needed
30-x=amount of 84% solution needed
..
12%x+84%(30-x)=19.2%*30
.12x+25.2-.84x=5.76
.72x=19.44
x=27
How many milliliters of the 12% solution does she need to make the mixture? 27