Question 79223
Solve for b, and then it has a=1/2bc2 the last 2 is a power 2
Do you mean:

a = {{{(1/2)bc^2}}} 
or 
a = {{{1/(2bc^2)}}}
:
A few brackets would help a lot.
:
The first case:
a = {{{(1/2)bc^2}}} 
Mult the equation by 2 and you have:
2a = {{{bc^2}}}
:
divide both sides by {{{c^2}}}
{{{(2a)/c^2}}} = b
:
:
The 2nd case:
a = {{{1/(2bc^2)}}}
Multiply both sides by {{{2bc^2}}}
{{{a*2*b*c^2)}}} = 1
:
Divide both sides by {{{(2ac^2)}}}
b = {{{1/((2ac^2))}}}
:
It is important that you make it clear what the problem is. A lot of tutors
will pass over a problem that is ambiguous.