Question 79237
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Good morning I'm stuck with the following problems! 

                {{{(4/5)x - 3 = 2}}} 

Clear of fractions by multiplying every term by 5.
Use {{{5/1}}} to multiply by the first and use 
just {{{5}}} to multiply the other two terms by

            {{{(5/1)(4/5)x - (5)3 = (5)2}}}

              4x - 15 = 10

Add 15 to both sides

                   4x = 25

Divide both sides by 4

                  {{{(4x)/4 = 25/4}}}

                  {{{x = 25/4}}}  


7a + 8b = 5c solve for a 

Isolate all terms with a on the left side.
Do this by subtracting 5b from both sides:

             7a = 5c - 8b

Draw a line under both sides and divide 
by 7

              {{{(7a)/7 = (3c-8b)/7}}}}

Cancel the 7's on the left:
    
                {{{a = (3c-8b)/7}}}}

Leave the answer just like that.

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find the x intercept: 7x + 5y = 3 

To find the intercept for either letter
x or y, substitute 0 for the OTHER
letter and solve.

So we substitute 0 for the OTHER letter
y and solve for x.

       7x + 5y = 3
     7(0) + 5y = 3
        0 + 5y = 3
            5y = 3

Divide both sides by 5

            {{{(5y)/5 = 3/5}}}

              {{{y = 3/5}}}  

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solve: 3(2 - x) > x + 2

         6 - 3x > x + 2

Get rid of the x on the right by 
subtracting x from both sides:

        6 - 4x > 2

Get rid of the 6 on the left by 
subtracting 6 from both sides

          -4x > -4 

Divide both sides by -4 remembering
the rules:

1. When you divide (or multiply) 
   both sides of an inequality
   by a NEGATIVE number, you MUST
   reverse the sign of inequality.

2. When you divide (or multiply) 
   both sides of an inequality
   by a POSITIVE number, you DO NOT
   reverse the sign of inequality.

This is the first case, so we
reverse the sign of inequality:

             {{{(-4x)/(-4) < (-4)/(-4)}}} 
                
                x < 1

To write the solution is interval notation
we write:

               (-<font face = "symbol">¥</font>, 1)

Edwin</pre>