Question 935514
Coin count
{{{D=Q}}}
{{{Q=(1/3)N}}}
So,
{{{D=(1/3)N}}}
Money count
{{{5N+10D+25Q=500}}}
Substituting,
{{{5N+10(1/3)N+25(1/3)N=500}}}
{{{(5+10/3+25/3)N=500}}}
{{{(15/3+10/3+25/3)N=500}}}
{{{(50/3)N=500}}}
{{{N=30}}}
Then,
{{{D=Q=(1/3)(30)}}}
{{{D=Q=10}}}
30 nickels, 10 dimes, 10 quarters