Question 79097
multiply: (3x-30)/(x^2-4x) times (8x)/(10-x)
Factor where you can to get:
[3(x-10)/x(x-4)]*[-8x(x-10)]
Cancel where you can to get:
[3/(x-4)]*[-8/1]
Multiply to get:
[-24/(x-4)
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PROBLEM #2 
Simplify 
(m^2)/(8) divdied by (m^5)/(16)
Invert the denominator to get:
(m^2)/8 times 16/(m^5)
Cancel where you can to get:
2/(m^3)
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Cheers,
Stan H.