Question 935421
y + z = 2
2x + 3z = 5
x + y + z = 3
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put the system of linear equations into standard form
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y + z = 2
2x + 3z = 5
x + y + z = 3
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solution by matrix method:
x = 1
y = 1
z = 1
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now by elimination:
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-3(y + z = 2)
2x + 3z = 5
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-3y - 3z = -6
2x + 3z = 5
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add the two equations:
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-y = -1
y = 1
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2x + 3z = 5
x + 1 + z = 3
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2x + 3z = 5
-3(x + z = 2)
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2x + 3z = 5
-3x - 3z = -6
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add the two equations:
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-x = -1
x = 1
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y + z = 2
1 + z = 2
z = 1
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solution by elimination:
x = 1
y = 1
z = 1
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