Question 935340


the slope–intercept form {{{y = mx + b}}}, or the form {{{x = c}}}.


({{{-5}}},{{{4}}}); {{{m= (3/2)}}}

{{{y = mx + b}}}...plug in {{{x}}} and {{{y}}} value from given point, and slope

{{{4 =(3/2)(-5) + b}}}

{{{4 =-15/2 + b}}}

{{{8/2 +15/2 =b}}}

{{{23/2 = b}}}



so, your equation is: {{{y =(3/2)x + 23/2}}}

{{{drawing( 600, 600, -10, 10, -10, 10,circle(-5,4,.13),locate(-5,4,p(-5,4)), graph( 600, 600, -10, 10, -10, 10, (3/2)x + 23/2)) }}}