Question 935341

the slope–intercept form {{{y = mx + b}}}, or the form {{{x = c}}}.


({{{-5}}},{{{4}}}); {{{m= -(2/5)}}}

{{{y = mx + b}}}...plug in {{{x}}} and {{{y}}} value from given point, and slope

{{{4 =-(2/5)(-5) + b}}}

{{{4 =-(2/cross(5))(-cross(5)) + b}}}

{{{4 =-2/-1 + b}}}

{{{4 =2 + b}}}

{{{4 -2 = b}}}

{{{b=2}}}

so, your equation is: {{{y =-(2/5)x + 2}}}

{{{drawing( 600, 600, -10, 10, -10, 10,circle(-5,4,.13),locate(-5,4,p(-5,4)), graph( 600, 600, -10, 10, -10, 10, -(2/5)x + 2)) }}}