<PRE><B>Question 935308</B>
A 6 Liter solution is 60% HCL acid. How much of this must be taken out and be replaced with water to reduce the solution into 45% HCL acid?
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let x=amount of 60% acid solution to be removed and replaced with water
6-x=amount of 60% acid solution  remaining
..
60%(6-x)=45%*6
3.6-.6x=2.7
.6x=.9
x=1.5 liters
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