Question 935308
x = liters of 60% HCL acid/water = 40% HCL water/acid
y = liters of 100% water
z = liters of 45% HCL acid/water = 55% HCL water/acid
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z = 6
0.40x + 1.00y = 0.55z
x + y = z
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put the system of linear equations into standard form
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z = 6
0.40x + 1.00y - 0.55z = 0
x + y - z = 0
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x = liters of 60% HCL acid/water = 40% HCL water/acid = 4.5
y = liters of 100% water = 1.5
z = liters of 45% HCL acid/water = 55% HCL water/acid = 6
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answer:
replace 1.5 liters of 60% HCL acid with pure water
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