Question 934313

{{{y = x -4}}}.....eq.1...substitute in eq.2
{{{4x + y = 26}}}...eq.2
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{{{4x + x -4 = 26}}}...eq.2...solve for {{{x}}}

{{{5x = 26+4}}}

{{{5x = 30}}}

{{{x = 30/5}}}

{{{x = 6}}}


{{{y = x -4}}}.....eq.1 substitute in {{{6}}} for {{{x}}}

{{{y = 6 -4}}}

{{{y = 2}}}

{{{ graph( 600, 600, -10, 10, -10, 30, x -4, -4x+26) }}}