Question 79180
Solve the system of equations:
1) {{{x-3y = 2}}}
2) {{{x+2y = -3}}}
Rewrite equation 1) as:
1) {{{x = 3y+2}}} and substitute for x in equation 2)
2a) {{{(3y+2)+2y = -3}}} Simplify and solve for y.
{{{5y+2 = -3}}} Subtract 2 from both sides.
{{{5y = -5}}} Divide both sides by 5.
{{{y = -1}}} Now substitute this for y in equation 1) and solve for x.
{{{x = 3y+2}}}
{{{x = 3(-1)+2}}}
{{{x = -1}}}
The solution is: (-1, -1)