Question 934314

{{{x-2y = -25}}}.....eq.1
{{{3x -y = 0}}}.....eq.2
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{{{x-2y = -25}}}.....eq.1...solve for {{{x}}}

{{{x= 2y -25}}}...substitute in eq.2


{{{3(2y -25) -y = 0}}}.....eq.2..solve for {{{y}}}

{{{6y -75 -y = 0}}}

{{{5y= 75}}}

{{{y= 75/5}}}

{{{y= 15}}}

now find {{{x}}}

{{{x= 2y -25}}}

{{{x= 2*15 -25}}}

{{{x=30 -25}}}

{{{x= 5}}}


solution is: 

{{{x= 5}}} and {{{y= 15}}}

means, the intersection point of these two lines is at ({{{5}}},{{{15}}})


{{{ graph( 600, 600, -10, 10, -10, 20, x/2+25/2, 3x) }}}