Question 935158
T is older than G, and the difference of their ages is 40.
t = g + 40
:
If forty years ago T was half as old as G will be in forty years,
t - 40 = {{{1/2}}}(g+40)
t - 40 = {{{1/2}}}g + 20
t = {{{1/2}}}g + 20 + 40
t = {{{1/2}}}g + 60
replace t with (g+40)
g + 40 = {{{1/2}}}g + 60
g - {{{1/2}}}g + 60 - 40
{{{1/2}}}g = 20
multiply both sides by 2
g = 40 yrs
therefore, obviously:
t = 80 yrs
:
 what is the sum of their ages? 120 yrs