Question 935165


Then substitute the value of {{{x}}} from {{{(x+2)}}} to the given equation above.

{{{x+2=0}}}

{{{x = -2}}}

{{{(-2)^5+p(-2)^3+2(-2)^2-6(-2)-8= 4}}}

Then solve for {{{p}}}
 
{{{-32-8p+8+12-8=4}}}

{{{-20-8p=4}}}

{{{-20-4=8p}}}

{{{-24=8p}}}

{{{p=-3}}}