Question 935166


Since the average increased by {{{29.7}}} and there were a total of {{{10}}} numbers, it means the incorrect number was {{{29.7*10=297}}} greater than the correct number.

Say, the correct number was {{{abc}}} (where {{{a}}}, {{{b}}} and {{{c}}} are the digits of the {{{3}}} digit number)
Then the incorrect number was {{{cba}}}.

{{{100c + 10b + a-(100a + 10b + c) = 297}}}
{{{99c-99a = 297}}}
 {{{99(c-a)= 297}}}
{{{(c-a)= 297/99}}}
So {{{c-a = 3}}}