<PRE><B>Question 935139</B>
If the complement of an angle is 5° less than one-sixth of its supplement, find the measure of the angle.



;et angle be x
complimentary angle = (90-x)

supplementary angle = (180-x)
0n-sixth = (180-x)/6
5 less than = (180-x)/6 - 5

(90-x) =((180-x)/6) -5

90+5 = (180-x)/6 +x

95 = (180-x+6x)/6
570 = 180+5x
390 = 5x

x= 78 deg




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