<PRE><B>Question 935128</B>
x length by 2x-1. 
the width of the outer rectangle is  x+3 and the length  x+5.


Area of outer region= Area of outer rectangle - area of inner rectangle

(x+3)(x+5) - x(2x-1)

x^2+8x+15 -2x^2-x

-x^2+7x+15

Area of outer region=-x^2+7x+15

Perimeter = 2(l+w)

= 2(x+3+x+5)

=2(2x+8)

4x+16 =24

4x=8
x=2


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