Question 935073


if {{{(x+ 1)/y = 1}}} =>{{{y=x+ 1}}} 

and {{{(y-1)/z =1}}}=>{{{z=y-1}}}...substitute  {{{y}}}

=>{{{z=x+1-1}}}
=>{{{z=x}}}


then the value of {{{xyz=x*(x+1)x=x^2(x+1)=x^3+x^2}}}