Question 935085
{{{x = ( 7 + 4sqrt (3 ))}}} , then the value of {{{(x^2+1)/x^2}}} is:


{{{(( 7 + 4sqrt (3 ))^2+1)/( 7 + 4sqrt (3 ))^2}}}


{{{(( 7 + 4*1.73 )^2+1)/( 7 + 4*1.73)^2}}}


{{{((13.92)^2+1)/( 13.92)^2}}}


{{{(193.7664+1)/( 193.7664)}}}


{{{194.7664/193.7664}}}


{{{1.005160853481305}}} which is approximately {{{1}}}