Question 934827
x={{{(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))}}}

y=1

x-y

{{{(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))}}} -1

{{{(sqrt(3)+sqrt(2)-sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))}}}

{{{ 2sqrt(2)/(sqrt(3)-sqrt(2))}}}

x-3y

{{{(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))}}} -3

{{{(sqrt(3)+sqrt(2)-3sqrt(3)+3sqrt(2))/(sqrt(3)-sqrt(2))}}}


{{{(4sqrt(2)-2sqrt(3))/(sqrt(3)-sqrt(2))}}}


{{{(2(2sqrt(2)-sqrt(3)))/(sqrt(3)-sqrt(2))}}}


{{{(x-y)/(x-3y)= (2sqrt(2)/(sqrt(3)-sqrt(2)))/((2(2sqrt(2)-sqrt(3)))/((sqrt(3)-sqrt(2))))}}}

{{{(sqrt(2))/(2sqrt(2)-sqrt(3))}}}