<PRE><B>Question 934939</B>
LET A=SMUGGLER STARTING POINT @ 6:OO 
B=SMUGGLER POINT @ 6:30
C= POLICE POINT WHEN DETECTING THE SMUGGLER @6:30 
D= POINT WHERE THE SMUGGLER INTERCEPTED BY THE POLICE @ TIME 8:30
rEQUIRED IS THE COURSE OF THE POLICE DURING INTERCEPTION==? 

@ 6:30 THE SMUGGLER TRAVELED THE DISTANCE OF AB @ RATE 200KPH TIME TRAVELED IS 0.5HR

AB=VT
AB=200*.5
AB=100KM
@ TIME 8:30 THE SMUGGLER TRAVELED AT DISTANCE BD @ THE RATE OF 200KPH
SO..BD=200(8.5-6.5)=400KM

SEE ATTACHED DIAGRAM FOR THE BASIS OF GETTING THIS COURSE 
403.89N 18.46DEG E------------ THE ANSWER 

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