Question 934866
n(A)=15
n(B)=15
n(AUB) =n(A)+n(B)-n(A n B)
n(AUB) can be maximum when n(AnB) is zero
so max value of n(AUB) =15+15-0
                        =30
n(AUB) can be minimum when n(AnB)  is maximum.that means n(AnB) =15
min n(AUB)=15+15-15
           =15
n(AnB) is minimum when n(AUB) is maximum and n(AnB) is  maximum when n(AUB) is minimum. .
hence max n(AnB)=15
min n(AnB)=0