Question 935055
The length of a rectangle is 7yds
less than three times the width, and the area of the rectangle is 66yds^2. Find the dimensions of the rectangle. 
<pre>
Let width be W
Then length = 3W - 7
We then get: W(3W - 7) = 66
{{{3W^2 - 7W - 66 = 0}}}
(W - 6)(3W + 11) = 0 
W - 6 = 0                   OR                 3W + 11 = 0
W, or width = {{{highlight_green(6)}}} yds       OR                 3W = - 11(ignore)   
Length: 3(6) - 7, or 18 - 7, or {{{highlight_green(11)}}} yds