Question 935059
x+3y<=30 and 3x+y<=30, and then surround each inequality with triple left and triple right curly braces
for rendering purposes.


{{{x+3y<=30}}}
{{{3y<=-x+30}}}
{{{y<=-x/3+10}}}



{{{3x+y<=30}}}
{{{y<=-3x+30}}}


The system can be expressed as {{{system(y<=-x/3+10,y<=-3x+30)}}}


You graph each line and then use the inequality statements to show which region of points
satisfies BOTH statements.  (I have not figured out yet how to make the graph properly render
to show this type of graphed system of inequalities.)


This graph is not complete:
{{{graph(-12,12,0,35,-x/3+10,-3x+30)}}}
In fact, the entire graph code rendering is failing, so you probably see nothing there.