Question 935051
Special triangles, two of them.  30-60-90 type, a RIGHT TRIANGLE, each.
Hypotenuse is a side of the equilateral triangle.
Short leg is HALF the hypotenuse length.  The height, is the other leg, given as size 8 units.


Let x=short leg size of the special right triangle.
PYTHAGOREAN THEOREM FORMULA,  {{{x^2+8^2=(2x)^2}}}.
According to the way the x variable was assigned, you really want 2x, solvable.  The base for the equilateral triangle is 2x.


Area for the equilateral triangle will be {{{(1/2)(2x)(8)}}}, typical formula applied for area of triangle.  This will be {{{8x}}}, or {{{4*2x}}}.


I simply did not solve x for you.