Question 935023
Let the first odd integer be x.
The second one would be x+2
The third one would be x+4
The fourth one would be x+6.

How do I know the second one is x+2? Just plug in 1 as the odd integer(x). For the second one, x+2= 3, then x+4= 5 and the last one, x+6=7. Try it with other odd integers and you will get the same results.

Now, we can solve algebraically

x+ (x+2) + (x+4) + (x+6)   = 152
4x + 12                    = 152
4x + 12 - 12               = 152-12
4x                         = 140
x                          = 35

So, the integers are 35, 37, 39 and 41. The smallest would be 35.