Question 934888
36 possible outcomes:
___1_2_3__4__5__6
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_7__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12
...
P(x > 9  0r even) = 10/36 + 18/36 - 5/36  (can't count twice)
Let You check the counting