Question 934955

Find three consecutive odd intergers such that twice the sum of the first and third more than the second by fifteen
<pre>
Let first integer be F
The 2nd and 3rd are: F + 2, and F + 4, respectively
Then: 2(F + F + 4) = F + 2 + 15
2(2F + 4) = F + 17
4F + 8 = F + 17
4F - F = 17 - 8
3F = 9
F, or 1st = {{{9/3}}}, or {{{highlight_green(3)}}}
2nd integer: 3 + 2, or {{{highlight_green(5)}}}
3rd integer: 3 + 4, or {{{highlight_green(7)}}}