<PRE><B>Question 934961</B>
find three consecutive integers such that the sum of twice the second and three time the third is five less than six times the first.
***
let x=1st consecutive integer
let x+1=2nd consecutive integer
let x+2=3rd consecutive integer
..
2(x+1)+3(x+2)=6x-5
2x+2+3x+6=6x-5
x=13
x+1=14
x+2=15xx
1st consecutive integer=13
2nd consecutive integer=14
3rd consecutive integer=15</PRE>