Question 79114
you need to define the dimensions of the rectangles in terms of length (l) and width (w) and 60 yards of fence


A. in this case, 2 lines of fence correspond to the length and 5 lines to the width ... so 2l+5w=60 ... or l=(60-5w)/2


since area equals l times w, substituting for l gives ... a=((60-5w)/2)*w ...   area = {{{(60w-5w^2)/2}}}


B. similar to A, 3 lines are equal to the length and 3 lines are equal to the width ... so 3l+3w=60 ... or l=20-w


again, substituting gives ... a=(20-w)*w ... area = {{{20w-w^2}}}


you could also solve for w in terms of l and substitute to get the areas in terms of l