Question 934833
Explanation needed for how X and x are used in the problem.
{{{X-2y<=4}}} contains no x.


The line boundary between the two dimensional regions contain infite points.
Just pick any X you want and find the corresponding y.
{{{-2y<=4+X}}}
{{{y>=-2-X/2}}}
{{{highlight_green(y>=-X/2-2)}}};


If instead you want the x-intercept for the reference line, then just set y=0
and solve for X.  This must be what you are really after finding.
Going back to the original inequality, {{{X-2y<=4}}}, if y=0, then
{{{X-2*0<=4}}}
{{{X<=4}}}
you really want {{{X=4}}}.