Question 934753
i believe the driving link rotates in a circle agound the end of the fixed link.
this forces the driven link to do the same.


what you have then are 2 circles being rotated at the same time by the driving link.


the driving link is the radius of the driving circle.
the driven link is the radius of the driven circle.
the circles have the same radius so they are congruent.


since there is always the same distance between them, then they are always in the exact same position relative to each and the distance between the connecting link and the fixed link remain the same.


what you have is a parallelogram that is composed of the driving link and driven link always being equal and parallel to each other, and the connecting link and fixed link always being equal and parallel to each other.


if a quadrilateral has opposite side equal to each other, then the quadraliteral is a parallelogram and the opposite angles will always be equal to each other.


here's a demo on parallelograms that might be helpful.
<a href = "http://www.mathopenref.com/coordparallelogram.html" target = "_blank">http://www.mathopenref.com/coordparallelogram.html</a>


this link shows theorems relating to parallelograms.
check out theorem 2.
<a href = "http://www.sonoma.edu/users/w/wilsonst/courses/math_150/theorems/Parallelograms/default.html" target = "_blank">http://www.sonoma.edu/users/w/wilsonst/courses/math_150/theorems/Parallelograms/default.html</a>


since you know you have a parallelogram because the opposite sides will always be congruent to each other, then it follows that the links will always be parallel to each other.



take the fixed link and mark the left end A and the right end B.


take the connecting link and mark the left end D and the right end C.


your parallelogram is ABCD.


AB is always congruent to CD.
AC is always congruent to BD.