<PRE><B>Question 934701</B>
x = speed of first car
y = speed of second car
t = time of second car
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y = x + 3
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s = d/t
t = d/s
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time of first car:
t + 6/60 = 120/x
t = 120/x - 6/60
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time of second car:
t = 120/y
t = 120/(x + 3)
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equate times:
120/x - 6/60 = 120/(x + 3)
120/x - 120/(x + 3) = 6/60
120(x + 3)/x(x + 3) - 120x/x(x + 3) = 6/60
120(x + 3) - 120x = (6/60)x(x + 3)
120x + 360 - 120x = (6/60)xx + 3*(6/60)x
360 = (6/60)xx + 3*(6/60)x
(6/60)xx + 3*(6/60)x - 360 = 0
( (6/60)xx + 3*(6/60)x - 360 = 0 )/6
(1/60)xx + 3*(1/60)x - 60 = 0
( (1/60)xx + 3*(1/60)x - 60 = 0 )*60
(1/1)xx + 3*(1/1)x - 60*60 = 0
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answer:
xx + 3x - 3600 = 0
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