Question 934682
let rate of canoe be x mph
rate of current = y

Time taken by log to reach starting point = 2/y.....................(1)

he canoes for 1 hour at speed of (x-y) upstream

so distance he paddles = x-y

Return

downstream speed = (x+y)

Time taken to reach starting point = time to reach the crossing point + time taken for 2 miles
=(x-y)/(x+y) +2/(x+y)

2/y = 1+(x-y)/(x+y) +2/(x+y)

2/y = (x+y+x-y+2)/(x+y)

2/y = (2x+2)/(x+y)

2/y = 2(x+2)/(x+y)

1/y =(x+1)/(x+y)

x+y = xy+y

x=xy

y=1

rate of current = 1mph