Question 934557
The number of vacation days taken by employees of a company is normally distributed with a mean of 14 days and a standard deviation of 3 days. For the next employee, what is the probability that the number of days of vacation taken is less than 10 days?
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z(10) = (10-14)/3 = -4/3
P(x < 10) = P(z < -4/3) = normalcdf(-100,-4/3) = 0.09121 

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More than 21 days?
z(21) = (21-14)/3 = 7/3
P(x > 21) = P(z > 7/3) = normalcdf(7/3,100) = 0.00982
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Cheers,
Stan H.
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