<PRE><B>Question 934541</B>
1 yard = 3 feet
1 mile = 5280 feet
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(220 yard) * (3 feet/yard) * (1/5280 mile/feet)
(220) * (3) * (1/5280)
0.125 mile
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the moment the front of the train enters the tunnel:
distance from back of train to end of tunnel = tunnel length + train length
2 + 0.125 = 2.125 miles
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time elapsed between the moment the front of the train enters the tunnel and the moment the end of the train clears the tunnel:
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s = d/t
t = d/s
t = 2.125/40
t = 0.053125 hour
t = 0.053125 hour * (60 minutes/hour) = 3.1875 minutes
t = 3.1875 minutes * (60 seconds/minute) = 191.25 seconds
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