Question 934531
{{{-(20t^5u^2v^3)/(48t^7u^4v)=-(20/48)t^(5-7)u^(2-4)v^3}}}
{{{-(20t^5u^2v^3)/(48t^7u^4v)=-(5/12)t^(-2)u^(-2)v^3}}}
{{{-(20t^5u^2v^3)/(48t^7u^4v)=-(5/12)((v^3)/(t^2u^2))}}}