Question 78997
Does your first problem look like this:

{{{3x-12x^3}}}


{{{x(3-12x^2)}}} Factor out an x

{{{-x(12x^2-3)}}} Rearrange and factor out a negative 1

Now lets factor


*[invoke quadratic_factoring 12, 0, -3]


So we get:

{{{-x(6x+3)(2x-1)}}}