Question 934339
Rectangle A:
L and w for length and width.
{{{wL=180}}}
{{{w*20=180}}}
{{{w=9}}}, the width of rectangle A.


The lengths for width and length of rectangle B are some factor k of w and L.  {{{k<1}}} since we know rectangle B is smaller area while being similar to rectangle A.


Rectangle B:
{{{(kw)(kL)=45}}}, and we already now know w and L.
{{{k^2*wL=45}}}, and we also were given {{{wL=180}}}.
{{{k^2=45/(wL)}}}
{{{k^2=45/180}}}
{{{k^2=(1/4)}}}
{{{highlight(k=1/2)}}}


The perimeter for rectangle B using the factor k,
{{{2*(1/2)w+2*(1/2)L}}}
{{{w+L}}}
{{{9+20}}}
{{{highlight(perimeterOfRectangleB=29)}}}