Question 934244
Perpendicular lines have slopes that are negative reciprocals.
{{{(8/3)*m=-1}}}
{{{m=-3/8}}}
Use the point-slope form of a line,
{{{y-3=-(3/8)(x-(-2))}}}
{{{y-3=-(3/8)(x+2)}}}
{{{y-3=-(3/8)x-(3/4)}}}
{{{y=-(3/8)x-(3/4)+12/4}}}
{{{highlight(y=-(3/8)x+9/4)}}}
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{{{drawing(300,300,-6,6,-6,6,grid(1),circle(-2,3,0.3),graph(300,300,-6,6,-6,6,(8/3)(x+2)+3,-(3/8)x+9/4))}}}