Question 934205
<pre>
The exponential equation 
{{{B^C=A}}}
is equivalent to the logarithm equation  
{{{log(B,(A))=C}}}

Therefore,

The exponential equation 
{{{5^(-2)=1/25}}}
is equivalent to the logarithm equation  
{{{log(5,(1/25))=-2}}}

Edwin</pre>