Question 933413
The argument of the log function must be positive.
{{{5x-x^2>0}}}
{{{x(5-x)>0}}}
.
.
.
{{{graph(300,300,-2,6,-2,6,5x-x^2)}}}
The function is zero at {{{x=0}}} and {{{x=5}}} and positive in between so,
Domain: ({{{0}}},{{{5}}})