Question 934197
Mr. Jackson is 13 years less than 3 times as old as his son. Six years ago, he was 14 more than twice as old as his son then. Find each of their ages. 
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Equations:
J = 3S - 13
J-6 = 2(S-6)+14
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Substitute for "J" and solve for "S.
3S-13-6 = 2S-12+14
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S = -8+19
Son's age = 11 yrs
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Solve for "J"::
J = 3S-13
J = 33-13 = 20 yrs (Mr. Jackson's age now)
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Cheers,
Stan H.
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