Question 934056
Early factorization any coefficient due to the  {{{x^2}}} term is unnecessary here, because the coefficient is 1.  The term to Complete The Square is  {{{((-4)/2)^2=4}}}.  Try doing this way:


{{{x^2-4x=1}}}, added PLUS 1 to both members
{{{x^2-4x+4=1+4}}},  completing the square
{{{x^2-4x+4=5}}}
{{{(x-2)^2=5}}}
and you know what to do from here.