Question 934060
a=	1	,	b=	-4	,	c=	1
							
b^2-4ac=	16	+	-4				
b^2-4ac=	12

						
{{{	sqrt(	12	)=	3.46	}}}		
{{{y=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{y1=(-b+sqrt(b^2-4ac))/(2a)}}}							
y1=(	4	+	3.46	)/	2		
y1=(	3.73						
{{{y2=(-b-sqrt(b^2-4ac))/(2a)}}}							
y2=(	4	-3.46	) /	2			
y2= 	0.27