Question 934055
{{{y^2+4y-3=0}}}


{{{y^2+4y=3}}}


third term = (1/2co-efficient of middle term)^2

=(1/2(4))^2

=4

{{{y^2+4t+4 = 3+4}}}

{{{(y+2)^2= sqrt(7)}}}

take the square root

(y+2) = +/- {{{sqrt(7)}}}

y = -2+/-{{{sqrt(7)}}}