Question 934082
{{{2x^2 = 8x}}}

{{{2x^2-8x=0}}}

{{{2x(x-4)=0}}}

solutions:

if {{{2x=0}}}=> {{{x=0}}}

if {{{(x-4)=0}}}=> {{{x=4}}}


{{{drawing( 600, 600, -10, 10, -10, 50,circle(4,32,.13),circle(0,0,.13), graph( 600, 600, -10, 10, -10, 50, 2x^2,8x)) }}}