Question 933816
p(pass) = .85,  n = 3
......
P(x = 3) = binompdf(3, .85, 3)  0r (.85)^3
P(x = 0) = binompdf(3, .85, 0)   0r (.15)^3  (Note:  1-.85 = .15)
P(x ≥ 1) = 1 - P(0) = 1 - (.15)^3