Question 933770
1.{{{D+Q=47}}}
2.{{{10D+25Q=545}}}
From eq. 1,
{{{10D+10Q=470}}}
{{{10D=470-10Q}}}
Substitute,
{{{470-10Q+25Q=545}}}
{{{15Q=75}}}
{{{Q=5}}}
Then,
{{{D+5=47}}}
{{{D=42}}}
Forty two dimes and five quarters